Look in a row, column or box if there are x number of cells containing x possible numbers, where all the cells has the same possible numbers. Meaning, if a cell has only 2 and 3 as possible numbers, look for another cell in the same row, column or box which also has only 2 and 3 as possible numbers. If this exists, these cells must contain the number 2 or 3 as solution and we can remove 2 and 3 from the row, column or box.
| 1 |
9 |
2 |
|
|
7 |
8 |
6 |
|
| |
6 |
7 |
|
|
9 |
4 |
1 |
2 |
| 8 |
|
4 |
|
|
|
7 |
|
9 |
| |
|
9 |
|
5 |
|
2 |
|
|
| |
|
6 |
7 |
|
3 |
9 |
|
1 |
| |
1 |
|
|
9 |
|
6 |
4 |
|
| 9 |
|
|
|
|
|
1 |
2 |
8 |
| |
4 |
1 |
|
|
|
5 |
9 |
6 |
| 6 |
2 |
8 |
9 |
1 |
5 |
3 |
7 |
4 |
Here you see that R3 has two cells which have 3 and 5 as possible solutions. Therefore we can remove 3 and 5 from the other cells in R3, in this case 3 and 5 from R3C4 and 3 from R3C5.
| 1 |
9 |
2 |
345 |
34 |
7 |
8 |
6 |
35 |
| 35 |
6 |
7 |
358 |
38 |
9 |
4 |
1 |
2 |
| 8 |
35 |
4 |
12356 |
236 |
126 |
7 |
35 |
9 |
| 347 |
378 |
9 |
1468 |
5 |
1468 |
2 |
38 |
37 |
| 245 |
58 |
6 |
7 |
248 |
3 |
9 |
58 |
1 |
| 2357 |
1 |
35 |
28 |
9 |
28 |
6 |
4 |
357 |
| 9 |
357 |
35 |
346 |
3467 |
46 |
1 |
2 |
8 |
| 37 |
4 |
1 |
238 |
2378 |
28 |
5 |
9 |
6 |
| 6 |
2 |
8 |
9 |
1 |
5 |
3 |
7 |
4 |
This doesn't work only for 2 numbers in 2 cells. You can do it for the same numbers in 3 cells, 4 cells etc. This sudoku can be solved using DS and SiSo.